The Venn Diagram below models probabilities of three events, A,B, and C.

Answer:The two events are independent.Step-by-step explanation:By the conditional property we have:If A and B are two events then A and B are independent if:                   [tex]P(A|B)=P(A)[/tex]                                or                  [tex]P(B|A)=P(B)[/tex]( since,if two events A and B are independent then,[tex]P(A\bigcap B)=P(A)\times P(B)[/tex]Now we know that:[tex]P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}[/tex]Hence,[tex]P(A|B)=\dfrac{P(A)\times P(B)}{P(B)}\\\\i.e.\\\\P(A|B)=P(A)[/tex] )Based on the diagram that is given to us we observe that:Region A covers two parts of the total area.Hence, Area of Region A= 72/2=36Hence, we have:[tex]P(A)=\dfrac{36}{72}\\\\i.e.\\\\P(A)=\dfrac{1}{2}[/tex]Also, Region B covers two parts of the total area.Hence, Area of Region B= 72/2=36Hence, we have:[tex]P(B)=\dfrac{36}{72}\\\\i.e.\\\\P(B)=\dfrac{1}{2}[/tex]and A∩B covers one part of the total area.i.e.Area of A∩B=74/4=18Hence, we have:[tex]P(A\bigcap B)=\dfrac{18}{72}\\\\i.e.\\\\P(A\bigcap B)=\dfrac{1}{4}[/tex]Hence, we have:[tex]P(A|B)=\dfrac{\dfrac{1}{4}}{\dfrac{1}{2}}\\\\i.e.\\\\P(A|B)=\dfrac{2}{4}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}[/tex]Hence, we have:[tex]P(A|B)=P(A)[/tex]          Similarly we will have:[tex]P(B|A)=P(B)[/tex]